Question

A gas of volume 2000ml is kept in a vessel at a pressure 10^3 pascals at a temperature of 27°
c.if the pressure is increased to 10^5 pascals at the same temperature the volume of the gas become ?

Answer 1

$\boxed{BOYLE'S\:\: LAW :}$

In 1662, Robert Boyle founded the pressure - volume relationship of a dry gas at constant temperature.

Boyle states that, at constant temperature, the volume of a fixed mass of a dry gas is inversely proportional to its pressure.

$\boxed{Mathematical\:\:Expression :}$

P1V1 = P2V2 = K (At const. temperature)

The value of "k" however depends on the mass of dry gas and temperature of the gas.

____________________________________

$\bold{\huge{SOLUTION \: :}}$

____________________________________

✔ P1 = 1000 Pa

✔ V1 = 2000 ml

✔ P2 = 100000 cm Hg

✔ V2 = ? ml

By Boyle's law,

P1V1 = P2V2 ("T" is constant)

Or, V2 = (2000000/100000) ml

Or, V2 = 20 ml [ANSWER]

Answer 2

Answer:20ml

Explanation: given

P1=1000pa

V1=2000ml

P2=100000cmHg

V2=?

Sol:

We know that

P1V1=P2V2

SO THAT

1000×2000=100000×V2

By solving

We get V2=20ml