a gas of volume hundred CC is kept in a vessel at pressure can perform paskals maintained at a temperature of 24 degree celsius if now the pressure is increased to 10 power 5 Pascal keeping the temperature constant then the volume of the gas becomes
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4
10
100
1
1000
Solution :
Given
V1=100mL
P1=10.4Pa
V2=?
P2=105Pa
P1V1=P2V2
∴V2=P1V1P2=105×10010.4=10mL
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