A gas of volume of 15 ml at 300 K and 740 mm of Hg. Find
the temperature if volume becomes 10 ml at 760 mm
pressure of Hg.
(a) 209 K (b) 200 K (c) 205 K (d) 275 K
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The new temperature of gas will be (c) 205 K
Explanation:
Given data:
Initial volume = 15 mL
Initial pressure = 740 mmHg
Initial temperature = 300 K
Final temperature = ?
Final volume = 10 mL
Final pressure = 760 mmHg
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂T₁ / P₁V₁
T₂ = 760 mmHg ×10 mL ×300 k / 740 mmHg×15 mL
T₂ = 2280,000 K / 11100
T₂ = 205.4 K
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