A gas performs the work of expansion equal to 1000 J by absorbing the heat
1600 J. The internal energy change for the process is
(a) 2600 J
(b)-600 J
(c) 600 )
(d) 1300 J
Answers
Given info : A gas performs the work of expansion equal to 1000 J by absorbing the heat
1600 J.
To find : The internal energy change for the process is ...
solution : The gas performs the work of expansion, W = 1000 J [ it would be positive because work done on the system]
now heat absorb by gas (system) , q = 1600 J
from first law of thermodynamics,
q = ∆U + W
⇒1600 J = ∆U + 1000J
⇒∆U = 600 J
Therefore change in internal energy for the process is 600 J.
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Given:
- A gas performs the work of expansion equal to 1000 J by absorbing the heat
To find :
- The internal energy change for the process is ...
solution :
The gas performs the work of expansion, W = 1000 J [ it would be positive because work done on the system]
now heat absorb by gas (system) , q = 1600 J
from first law of thermodynamics,
q = ∆U + W
⇒1600 J = ∆U + 1000J
⇒∆U = 600 J
Therefore change in internal energy for the process is 600 J.
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