. A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%
oxygen, 16.82% phosphorus, and 10.30% fluorine. If the molecular mass is 184.1
g/mol, what is the molecular formula?
Answers
Answer:
Wyzant
ASK
Find an Online Tutor Now
CHEMISTRY
Joey R. asked • 11/21/19
maddie experimented with a gas sample. she found it contains 39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
she also determined that the molecular mass is 184.1 g/mol. help maddie determine the molecular formula.
plz help
Follow 2
Add comment
More
1 Expert Answer
By:
J.R. S. answered • 11/21/19
TUTOR 5.0 (92)
Ph.D. University Professor with 10+ years Tutoring Experience
ABOUT THIS TUTOR ›
This is similar to your previous question, except this also asks for the molecular formula.
Assuming 100 g of unknown, you have...
39.10 g C x 1 mol/12 g = 3.26 mole C
7.67 g H x 1 mol/1 g = 7.67 mol H
26.11 g O x 1 mol/16 g = 1.63 mol O
16.82 g P x 1 mol/31 g = 0.543 mol P
10.30 g F x 1 mol/19 g = 0.542
Dividing all by 0.542 we get
3.26/0.542 = 6 mol C
7.67/0.542 = 14 mol H
1.63/0.542 = 3 mol O
0.543/0.542 = 1 mol P
0.542/0.542 = 1 mol F
Empirical formula = C6H14PO3F. This has a molar mass of 72 + 14 + 31 + 48 + 19 = 184
Since the unknown has a molar mass of 184, the molecular formula is the same as the empirical formula
if it is correct then please follow me
Answer:
see the attachment ✌️❣️
