Question

A gas sample occupies a volume of 3.25 L at 24.5°c and 1825 mm of hg. determine the temperature at which the gas would occupy a volume of 4250 ml at 1.50 atm.

Answer 1

$\textbf{Answer is in Attachment !}$

Answer 2

Answer:

Temperature= 242.8K

Explanation:

V1=3.25 L

V2=4250 ml = 4.25 L

T1=24.5°C

(273 +24.5)=297.5 K

P2=1.5 atm = 151.95 kPa

P=1825 mm hg =243.25 kPa

T2= ?

We can find T2 using the formula,

(P1 × V1)/T1 = (P2 × V2)/T2

T2=(P2 × V2 × T1)/P1 × V1

T2=(151.95 × 4.25 × 297.5)/(243.25 × 3.23)

=242.8 K

So T2=242.8 K