Question

A gas $\ X_2Y_4$ at 35°C has RMS speed 12 m/s . On heating the gas twice to the original absolute temperature, the dimer totally disociated to give monomer. What is the RMS speed of $\ XY_2$ molecules at the given elevated temperature.

Please give correct answer with "EXPLAINATION" ​

Answer 1

Answer:

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Follow this Steps while solving ⬇️⬇️⬇️⬇️

X2Y2 gives Xy2

As they mention temperature double eruthe, so

T=2t

Mass (weight) =half eruthe so m/2

Rms formula ge values na apply madu

Next,

square root 3R(2t)/m/2

Denominator goes to up and mutilplied with 2 so we will get

Square root 3R4t /m

So, square root of 4 is 2

2 Na orge thege,. That's all.

Then Rms value will be 2

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Answer 2

Answer:

Refer to the above attachment