A gas that has a volume of 34.5 L, a temperature of 318 K, and an unknown pressure is placed in a new container that has a volume of 41.7 L. the temperature of the gas decreased 10 K. If the pressure of the gas in the NEW tank is 2.0 atm, what was the pressure of the gas in the original tank?
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0
Answer:
.026mol
Explanation:
pv=nrt
Answered by
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Explanation:
V1 = 34.5L
T = 318 K
P1 V1 = n R1 T1
→P1 34.5 = n ×318/12
→n = 34.5× 12P1 /318 .....(1)
V2 = 41.7L
T2= 308K
P2 = 2 atm ...
P2 V2= n R T2
→ n = 41.7×2×12/308 ....(2)
From (1) and (2),
0.28 = 1.301 P1
→ P1 = 0.21
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