a gas under constant pressure of 4.5 into 10 raise to 5 Pascal when subjected to 800 kilojoule of heat changes the volume from 0.5 m cube to 2.0 meter cube the change in internal energy of the gas is
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Answered by
16
here we have
the formula for change in internal energy is (u)
u=q(heat)+w(work done)
q=800
w=(p)*(vf-vi)(vf-vi=2-0.5)
w=4.5*10^5*1.5
w=675*10^3
so we get the change in internal energy
u=800+675000
w=675800
pls vote brainliest
the formula for change in internal energy is (u)
u=q(heat)+w(work done)
q=800
w=(p)*(vf-vi)(vf-vi=2-0.5)
w=4.5*10^5*1.5
w=675*10^3
so we get the change in internal energy
u=800+675000
w=675800
pls vote brainliest
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Answered by
5
Answer:given that,
Vf=2m3 ,Vi=0.5m3, P=4.5×Pa
Explanation:
dW=P(Vf-Vi)
=4.5×10*5(2-0.5)
=4.5×10*5(1.5)
dW= 6.75×10*5
dU=dQ-dW
=8×10*5-6.75×10*5
dU=1.25×10*5 J
Your answer is 1.25×10*5 J
Hope it helps you
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