Question

A gas undergoes a process such that v/t= constant, then the process is :

Answer 1

Final Answer : Isobaric Process.


For a fixed amount of gas,
V/ T is inversely proportional to Pressure on gas
Since,
V/ T = constant
=> P = constant
=> Isobaric Process.

Answer 2

If a gas undergoes a process such that V/T = constant, then the process is isobaric.

A gas undergoes a process such that V/T = constant, The process is..

According to universal gaseous equation, PV = nRT

• P is pressure of gas
• V is volume of gas
• n is number of moles of gas
• R is universal gas constant
• and T is temperature of gas in Kelvin.

Now, PV = nRT

⇒ P(V/T) = nR

⇒ (V/T) = nR/P

Under the condition of constant amount of gas and pressure. i.e., n & P are constants. Then (V/T) = constant.

We know, pressure and the amount of gas are constants in an isobaric process. This process is known as Charles' law.

Therefore a gas undergoes a process such that V/T = constant then the process is isobaric.

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