A gas undergoes a process such that v/t= constant, then the process is :
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Final Answer : Isobaric Process.
For a fixed amount of gas,
V/ T is inversely proportional to Pressure on gas
Since,
V/ T = constant
=> P = constant
=> Isobaric Process.
For a fixed amount of gas,
V/ T is inversely proportional to Pressure on gas
Since,
V/ T = constant
=> P = constant
=> Isobaric Process.
Answered by
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If a gas undergoes a process such that V/T = constant, then the process is isobaric.
A gas undergoes a process such that V/T = constant, The process is..
According to universal gaseous equation, PV = nRT
- P is pressure of gas
- V is volume of gas
- n is number of moles of gas
- R is universal gas constant
- and T is temperature of gas in Kelvin.
Now, PV = nRT
⇒ P(V/T) = nR
⇒ (V/T) = nR/P
Under the condition of constant amount of gas and pressure. i.e., n & P are constants. Then (V/T) = constant.
We know, pressure and the amount of gas are constants in an isobaric process. This process is known as Charles' law.
Therefore a gas undergoes a process such that V/T = constant then the process is isobaric.
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