Question

A gas undergoes change from state a to state b. In this process, the heat absorbed and work done by the gas is 5j and 8j, respectively. Now gas is brought back to a by another process during which 3j of heat is evolved. In this reverse process of b to a

Answer 1

Answer:

6J of work is done  by the surrounding on the gas

Explanation:

Given :

From process A to B :

q= -5J

Work done=w=8J

ΔUAB=q+W =+5-(-8)=-3J

From process B to A:

q=-3J

Δ UBA=+3

ΔUBA=q+W

3= - 3+W

W=+6J  

So 6J of work is done  by the surrounding on the gas