Question

a gas whose intial temperature is 27 degree celsius is compressed adiabatically to 8 times its initial pressure. if its gamma=1.5 find the rise in temperature in this transformation

Answer 1

The rise in temperature is 375 K.

Explanation:

Correct statement:

An ideal gas at 27∘C is compressed adiabatic-ally to 8/27 of its original volume. If γ=5/3, then the rise in temperature is

Given data:

Initial temperature "T1" = 27 degree Celsius = 300 K

Gamma "γ" = 5/3

For an adiabatic process TVγ−1= constant. Therefore

T1 / T2 = [V2 / V1]^γ−1

T2 = T1 [ V1 / V2]^γ−1

T2 = 300 [27/8]^5/3 - 1

T2 = 300 [27/8]^2/3

T2 = 675 K

ΔT= 675−300=375 K

Thus the rise in temperature is 375 K.

Also learn more

What is the temperature in kelvin of a gas if it is allowed to expand from 1.50 L to 4.50 L? The initial temperature is 10.0°C and pressure is constant throughout the change.

https://brainly.com/question/2930773

Answer 2

Answer:

answer of your question