A gas 'X' at -33°C is heated to 127°C at constant pressure. Calculate the percentage increase in the volume of the gas.
Answers
Answered by
12
Explanation:
T1 =-33℃ = -33 + 273 = 240 °k
T2 = 127 ℃= 127 + 273 = 400°k
as per Charles law,
V1/T1 = V2/T2
T2/T1 = V2/V1
V2/V1 = 400/240 = 5/3 = 1.6667
V2 =1.667*V1 = (166.67/100)*V1
so the % increase in Volume is
V2 - V1 = (1.667 - 1)*100 = 66.67%
Answered by
4
Answer:
T1 =-33℃ = -33 + 273 = 240 °k
T2 = 127 ℃= 127 + 273 = 400°k
as per Charles law,
V1/T1 = V2/T2
T2/T1 = V2/V1
V2/V1 = 400/240 = 5/3 = 1.6667
V2 =1.667*V1 = (166.67/100)*V1
so the % increase in Volume is
V2 - V1 = (1.667 - 1)*100 = 66.67%
Explanation:
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