Question

A gas X has Cp and Cv ratio as 1.4, at NTP 11.2 L of gas X will contain_______ number of atoms

Answer 1

ANSWER

C

v

C

p

=γ=1.4

Hence, the gas is diatomic.

Number of atoms = atoms in one molecule of gas × mole×N

A

=2×

22.4

V

×N

A

=2×

22.4

11.2

×6.02×10

23

=6.02×10

23