Question

A gas X having a volume of 1 litre at 10 degrees Celcius is heated. Its volume changes to 3 litres on heating and the pressure is simultaneously tripled. Calculate the new temperature required for the change

Answer 1

Answer:

Solution:- (A) 7.5

W=PΔV=nRΔT

⇒ΔT=

nR

PΔV

Given that:-

n=2 moles

P=1atm

V

i

=2L

V

f

=5L

ΔV=V

f

−V

i

=5−2=3L

∴ΔT=

2R

1×3

=

2R

3

Now, as we know that,

ΔU=nC

v

ΔT

Since the gas is diatomic.

∴C

v

=

2

5R

∴ΔU=2×

2

5R

×

2R

3

=7.5L−atm

Hence the change in interal will be 7.5L−atm.