Question

A gas X occupies volume of 22.4 litres at s.t.p. What volume will the gas occupy at the temperature of 273°C and pressure of 1520 mm Hg?

Answer 1

Hope this clarifies your query.

Answer 2

Answer:

The volume will be 22.4 litres

Explanation:

By combining Boyles law( $V$∝ $\frac{1}{P}$ ), Charles law (V∝ T), and Avogadro's law (V ∝ n), we get $V$ ∝ $\frac{nT}{P}$ or PV= a constant × T

Hence PV = nRT → equation 1

When gas is at STP, We can formulate this equation 1 as

$\frac{PV}{T} =nR$ = a constant for a certain mass of gas

Therefore, the volume of a gas at STP is  $\frac{PV}{T} =\frac{P_0V_0}{T_0}$ →equation 2

Given that X gas occupies a volume of 22.4 liters at STP  $V_0 =22.4$Litres

In STP the temperature $T_o =0$ °C =0+273 =273K  

and Pressure $P_0$ =760 mm Hg = 1 atm

P = 1520 mm Hg = 2 atm and T= 273 °C=273+273 =546K

By substituting these values in equation 2

The volume of the gas will be,  $V=\frac{P_0V_0T}{PT_0}$  = $\frac{(1*22.4*546)}{(2*273)}$

                                                        =$\frac{12230.4}{546}$ = 22.4 litres

Therefore the volume of the gas will be 22.4 liters