Question

A gas 'Z' which changes the colour of KMnO4 solution and of lead acetate solution, But has no effect on lime water when passed through it.​

Answer 1

Sulphur dioxide (SO

2

) is passed through an acidified solution of potassium permagnate (KMnO

4

) which is purple in colour.On doing so, sulphur dioxide being a strong reducing agent ,reduces the purple coloured solution to form a colourless solution .

2KMnO

4

+5SO

2

+2H

2

O→K

2

SO

4

+2MnSO

4

+2H

2

SO

4

(purple) (colourless)

Answer 2

Answer:

Hydrogen sulphide

Explanation:

Hydrogen sulphide(H2S) has no effect on lime water but Sulphur dioxide(SO2) turns lime water milky.