Question

A gaseous compound x contained 44.4% c, 51.9% n and 3.7% h. Under like condition 30 cm3 of x diffused through a pinhole in 25 sec and the same volume of h2 diffused in 4.81 sec. The molecular formula of x is

Answer 1

Hey dear,

● Answer- C2N2H2

● Explanation-
Let's calculate empirical formula first-
C = 44.4/12 = 3.7
N = 51.9/14 = 3.7
H = 3.7/1 = 3.7

Empirical formula is CNH.
Empirical formula mass = 12+14+1 = 27 g

Molecular formula mass = 25×2/4.81 = 54 g

Multiplying factor = molecular formula mass / empirical formula mass = 54/27 = 2

Molecular formula = 2 × Empirical formula
Molecular formula = 2 × CNH
Molecular formula = C2N2H2

Hope this is helpful...