A gaseous excited hydrogen like species with nuclear charge Z can emit radiations of six different photon energies. The principal quantum number of the excited state is:
Answers
Answered by
0
Answer:
The value of the electrons Z in the excited state of the hydrogen atom will be 2 since the atomic number of hydrogen is 1.
We know that the value of energy is having a formulae E=Rh*Z^2/n^2. Where the value of n is the principal quantum number.
So, on putting the value of Rh as 13.6eV and the Z to be 2 we will get the value of n^2 to be approximately 9 and then the value of n or the principal quantum number will be 3.
Similar questions
Accountancy,
6 months ago
Computer Science,
6 months ago
Math,
6 months ago
Math,
1 year ago
English,
1 year ago
World Languages,
1 year ago