A gaseous hydrocarbon gives upon combustion 0.72g water and 3.08g CO2 . What is the hydrocarbon’s empirical formula?
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Answered by
1
Answer:
(a) The electronic configuration represents
2s22p5= fluorine = most electronegative element
3s23p5 = chlorine
4s24p5 = bromine
5s25p5 = iodine
Answered by
1
Question:
A gaseous hydrocarbon gives upon combustion 0.72 g of H2O and 3.08 g of CO2. The empirical formula of the hydrocarbon is
Solution:
We know,
Hydrocarbon contains C and H. Let he formula be
And 18 g of H₂O consist of 2 moles of H atoms.
Then, 0.72 g of H₂O consist of:
2/18 x 0.72 = 0.08
So, 0.72 g of H₂O consist of 0.08 moles of H atoms.
We know,
44 g of CO₂ consist of 1 mole of C atom.
Then, 3.08 g of CO₂ consist of:
1/44 x 3.08 = 0.07
So, 3.08 g of CO₂ consist of 0.07 mole of C atom.
Then, ratio of x and y :
= 0.07/0.08
= 7 : 8
So, empirical formula is C₇H₈.
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