Chemistry, asked by nikitakalita65, 4 months ago

a gaseous mixture consists of N₂, H₂ and NH3
in equilibrium - What is the number
of phases?
a) One
b) Two
c) Three​

Answers

Answered by Soumyadaggubati
0

Answer:

Initial mole ratio N2:H2 is 1:3

At equilibrium, 50% of N2, H2 has reacted and equilibrium pressure is P

N  

2

​  

+3H  

2

​  

→2NH  

3

​  

 

y3y2y

At equilibrium, 50% of each reactant reacted, the number of moles will become half.

The mole of N2=y−  

2

y

​  

 

The moles of H2=3y−  

2

3y

​  

 

THE moles of NH3=  

2

2y

​  

 

Total moles at equilibrium=  

2

y

​  

+  

2

3y

​  

+  

2

2y

​  

=3y

Partial pressure of H2=  

Totalmoles

MolesofH2

​  

×Totalpressure=  

2

3y

​  

×  

3y

1

​  

×P=  

2

P

Explanation:

Similar questions