Question

a gaseous mixture consists of two 2 moles of argon and 4 moles of O2. the molar specific heat at constant volume is​

Answer 1

Answer:

13R/6

Explanation:

molar specific heat at constant volume(Cv) = (n1c1+ n2c2)/n1+n2

here, c1 (pertaining to argon which is monoatomic)= 3R/2

here, c2(pertaining to oxygen which is diatomic)= 5R/2

n1= 2

n2= 4

Cv= {2*(3R/2) + 4*(5R/2)}

      -----------------------------

                      6

Cv= 3R +10R

       ------------

              6

Cv= 13R/6