Question

A gaseous mixture contain 56g of n2 44g of co2 and 16g of ch4. The total pressure of mixture is 720mmhg the partial pressure of ch4 in mmhg would be?

Answer 1

Answer:

Answer: 180 mm Hg

Explanation:

Answer: 180 mm Hg

Explanation: Partial pressure is calculated by multiplying the mole fraction by the total pressure.

p_i=x_i\times P_{total}

p= partial pressure

x = mole fraction=\frac{\text {moles of that substance}}{\text {Total moles}}[/tex]

Moles is calculated by using the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

{\text {Moles of} N_2}=\frac{56g}{28g/mol}=2mole

{\text {Moles of} CO_2}=\frac{44g}{44g/mol}=1mole

{\text {Moles of} CH_4}=\frac{16g}{16g/mol}=1mole

Total moles = 2+1+1=4

Mole fraction of methane=[/tex]\frac{1}{4}=0.25[/tex]

p_{methane}=0.25\times 720mmHg=180mmHg