Question

A Gaseous Mixture Contain 60% Nitrogen 15% Oxygen And 25% Carbon Dioxide By Mass.Calculate The Mole Fraction Of Each Gas.

Answer 1

Answer:

Molar mass of nitrogen gas = 28 g

Molar mass of oxygen gas = 32 g

Molar mass of carbon dioxide gas = 44 g

mass of nitrogen = 60 g

mass of oxygen = 15 g

mass of carbon dioxide = 25 g

Number of moles (n)  = Given mass / Molar mass

nN2 =  60 /28  = 2.1428 moles

nO2 = 15/ 32  = 0.468 moles

nCO2 = 25 /44 = 0.568 moles

Total number of moles = 2.1428 + 0.468 + 0.568 = 3.1788 moles

Mole fraction of N2 = 2.1428 / 3.1788 = 0.674  

Mole fraction of O2 =  0.468/ 3.1788 = 0.1472  

Mole fraction of CO2 = 0.568 / 3.1788 = 0.1786