Question

A gaseous mixture contain equal masses of CH4 ,O2 and SO2. If the total pressure is 10atm. Then the partial pressure of CH4 in the mixture is

(a). 60/7atm
(b). 40/7atm
(c). 5atm
(d). 30/7 atm

plz tell m correct ans... I will mark uh as a brainlist......

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Answer 1

Given:

Equal masses of CH4, O2 and SO2.

Total Pressure, P = 10 atm

To Find:

Partial pressure of CH4 in the mixture.

Calculation:

- Let the mass of each of the gases be 'w' gm'.

- Mole fraction of gas CH4 = (w/16) / (w/16 + w/32 + w/64)

⇒ X = (1/16) / (7/64)

⇒ X = 4/7

- Partial pressure of CH4, P(CH4) = X × P

⇒ P(CH4) = 4/7 × 10

⇒ P(CH4) = 40/7 atm

- Hence, the the partial pressure of CH4 in the mixture is 40/7 atm.

- So the correct answer is option (b) 40/7 atm.