Question

a gaseous mixture containing two hydrocarbons carbons XAnd Y of volume 44.8 lit when passes through ammonical ​

Answer 1

Answer:

no. of moles, n = W / MM = V/22.4

nO2 = 32/32 = VO2/22.4

VO2 = 22.4

nH2 = 3/2 =VH2/22.4

VH2 = 1.5×22.4 = 33.6

Total volume occupied = 22.4 + 33.6

= 56 lit.

Option 3 is correct.

Explanation: