a gaseous mixture containing two hydrocarbons carbons XAnd Y of volume 44.8 lit when passes through ammonical
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Answered by
1
Answer:
no. of moles, n = W / MM = V/22.4
nO2 = 32/32 = VO2/22.4
VO2 = 22.4
nH2 = 3/2 =VH2/22.4
VH2 = 1.5×22.4 = 33.6
Total volume occupied = 22.4 + 33.6
= 56 lit.
Option 3 is correct.
Explanation:
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