Question

A gaseous mixture contains 1 mole of H2, 2 mole of He in a closed container, total pressure exerted by the mixture is 6atm, what is the partial pressure of H2 gas ?​

Answer 1

Answer:

We know that partial pressure of a gas is the product of the total pressure and the concentration or the mole fraction of a gas in the mixture.

Partial pressure = Total pressure × Mole fraction

Let the given mass of each gas be x.

We know that the atomic masses given below:

H

2

=2

He=4

CH

4

=16

So, we have the mole fraction of each gas which is given below:

H

2

=x/2

He=x/4

CH

4

=x/16

The total moles of the gas mixture =0.8125x

Now, to calculate the partial pressure of :H

2

Partial pressure = Total pressure × Mole fraction

=

0.8125x

2

x

×2.6

Partial pressure of H

2

=1.6 atm

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