a gaseous mixture contains 50% helium and 50% methane by volume. What is the percentage by mass of methane in the mixture?
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hell... ooo..!!
Molar and volume ratios will be same 1 : 1
therefore.. Mass of 1 mole CH4CH4 and HeHe will be 16 and 4g respectively.
Percentage by mass of CH4=MassofCH4TotalmassCH4=MassofCH4Totalmass×100×100
=1620=1620×100×100
=80%
hope this helps you.....!!
Molar and volume ratios will be same 1 : 1
therefore.. Mass of 1 mole CH4CH4 and HeHe will be 16 and 4g respectively.
Percentage by mass of CH4=MassofCH4TotalmassCH4=MassofCH4Totalmass×100×100
=1620=1620×100×100
=80%
hope this helps you.....!!
MacTavish343:
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