Question

A gaseous mixture contains 80% CH4 and 20% H, by mass. Density of this mixture at 27°C and at 760 mm Hg is​

Answer 1

Explanation:

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no. of moles of nitrogen gas =

$\frac{56}{28} \: = 2$

no . of moles of carbon-dioxide gas =

$\frac{44}{44} = 1$

no. of moles of methane =

$\frac{16}{16} = 1$

Total no. of moles in the mixture = 4

Thus, mole fraction of methane = X CH4

= 1 : 4

= P CH4 = P.X CH4

= X CH4

= $\frac{1}{4}$

P CH4 = 180 mm

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Answer 2

Answer:

no. of moles of nitrogen gas =

no . of moles of carbon-dioxide gas =

no. of moles of methane =

Total no. of moles in the mixture = 4

Thus, mole fraction of methane = X CH4

= 1 : 4

= P CH4 = P.X CH4

= X CH4

=  

P CH4 = 180 mm

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