Question

A gaseous mixture contains hydrogen and N2 in the volume ratio of 1:2 under STP conditions. Their molar ratio in the mixture is​

Answer 1

Explanation:

this molar rature in the mixture is also 1:2

Answer 2

Given,

The ratio of the volume of hydrogen and nitrogen in the given mixture is = 1:2

To find,

The molar ratio of the two gases.

Solution,

The condition is STP is already mentioned in the question. And, in STP the volume of 1 mole of any gas is always 22.4 litres.

Let, the normal volume of the hydrogen and nitrogen

= 1x and 2x units

(Assume x as a variable to do the further mathematical calculations.)

Now,

22.4 litres of hydrogen = 1 mole

1 litre of hydrogen = 1/22.4 mole

1x litres of hydrogen = x/22.4 mole

And,

22.4 litres of oxygen = 1 mole

1 litre of oxygen = 1/22.4 mole

2x litres of oxygen = 2x/22.4 mole

So,

The molar ratio = x/22.4 : 2x/22.4 = x/22.4 × 22.4/2x

= x/2x = 1/2 = 1:2

Hence, their molar ratio will be 1:2