A gaseous mixture of C2H4 CH4 CO and N, at
400 K & 1 atm was added with excess of o2 &
subjected to sparking in a rigid container (volume
constant). If pressure of CO2 obtained at 400 K in
same volume is 0.9 atm and that ofH2O vapour is
0.8 atm. If moles of C2H4 and CH4 are equal then
calculate the pressure of each gas in the original mixture
Answers
Explanation:
In this reaction
C2H2 + CH4 + O2 --> CO2 + H2O
(Pa) (Pb) (Pc) (P1) (P2)
Given:
Partial pressure of oxygen Pc = 1 atm
Partial pressure of CO2 P1 = 0.9 atm
Partial pressure of H2O vapour P2 = 0.8 atm
since temperature and volume is constant
Volume = V
moles of C2H2 = CH4 = x moles
Both will have same partial pressure P = Pa = Pb
Pa + Pb + Pc = P1 + P2 = Pf
1.7 = 2P + 1
P = 0.35 atm
Answer The pressure of C2H2 = 0.35 atm and CH4 = 0.35 atm
Answer:
The pressure of C2H2 = 0.35 atm and CH4 = 0.35 atm
Explanation:
Step : 1 In this reaction
C2H2 + CH4 + O2 --> CO2 + H2O
(Pa) (Pb) (Pc) (P1) (P2)
Given:
Partial pressure of oxygen Pc = 1 atm
Partial pressure of CO2 P1 = 0.9 atm
Partial pressure of H2O vapour P2 = 0.8 atm
since temperature and volume is constant
Volume = V
moles of C2H2 = CH4 = x moles
Both will have same partial pressure P = Pa = Pb
Pa + Pb + Pc = P1 + P2 = Pf
1.7 = 2P + 1
P = 0.35 atm
The pressure of C2H2 = 0.35 atm and CH4 = 0.35 atm.
Step : 2 The simplest alkyne chemical molecule, known as acetylene chemically, is C2H2. Ethyne, Narcylen, and Vinylene are other names for acetylene. It is frequently employed as a fuel and a component of chemical compounds. The chemical compound acetylene, often known by its scientific name ethyne, has the formula C 2H 2 and the chemical formula H C C H. It is the most basic alkyne and a hydrocarbon. This colourless gas is frequently utilised as a fuel and a component of chemical compounds.
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