Question

a gaseous mixture was prepared by taking equal mass of CO and N2 if the total pressure of the mixture was found one atmosphere the partial pressure of the nitrogen in the mixture is

Answer 1

Given: nCO=nN2⇒pCO=pN2nCO=nN2⇒pCO=pN2

pCO+pN2=1atmpCO+pN2=1atm

⇒2pN2=1atm⇒2pN2=1atm

pN2=0.5atm

Answer 2

Answer: Partial pressure of Nitrogen in the mixture is 0.5 atm.

Explanation: We are given that the number of moles of $N_2\text{ and }CO$ are equal which means that their mole fractions are also equal.

Relation between partial pressure and mole fraction is given by:

$\chi _i=\frac{p_i}{P_{total}}$

As, $\chi _{N_2}=\chi _{CO}$

So, $p_{N_2}=p_{CO}$

Since, the total pressure = 1 atm (Given)

$P_{total}=p_{N_2}+p_{CO}$

$p_{N_2}+p_{CO}=1$

$2p_{N_2}=1$

$p_{N_2}=0.5 atm$