Chemistry, asked by divyanshu200310, 16 days ago

A gaseous sample consisting of 1.00 mol molecules is described by the equation of state pV m = RT(1 + Bp). Initially at 373 K, it undergoes Joule-Thomson expansion from 100 atm to 1.00 atm. Given that C p,m = (5/2)*R, μ =0.21 K atm −1 , B = −0.525(K/T) atm −1 , and that these are constant over the temperature range involved, calculate ΔT and ΔS for the gas.

Answers

Answered by maak13sharth
0

Answer:

Joule-Thompson Effect:

The Joule-Thompson Effect illustrates the isenthalpic expansion of a fluid on an valve, nozzle, flow element or porous media. The Joule-Thompson coefficient is the ratio of product of volume and expansion coefficient, divided by the specific heat.

Similar questions