Question

A gaseous solution contains 32g of O2 and 21g of N2, calculate the mole fraction of each component.​

Answer 1

Answer:

Formula to calculate Mole fraction is:

$\boxed{ \textbf{ Mole Fraction of (x}_n) = \dfrac{ \textbf{No of moles of Element n}}{\textbf{Sum of moles of all the Elements}}}$

According to the question,

Element 1 = Nitrogen (N₂)

⇒ Given Mass = 21 g

⇒ Molar Mass = 28 g

⇒ No of moles of N₂ = 21 g / 28 g

⇒ No of moles of N₂ = 3/4 = 0.75

Element 2 = Oxygen (O₂)

⇒ Given Mass = 32 g

⇒ Molar Mass = 32 g

⇒ No of moles of O₂ = 32 g / 32 g = 1

The mole fraction of N₂ is:

$x({N_2}) = \dfrac{0.75}{0.75 + 1}\\\\\\x(N_2) = \dfrac{0.75}{1.75}\\\\\\\boxed{ \bf{ x(N_2) = 0.428 }}$

The mole fraction of O₂ is:

$x({O_2}) = \dfrac{1}{0.75 + 1}\\\\\\x(O_2) = \dfrac{1}{1.75}\\\\\\\boxed{ \bf{ x(O_2) = 0.571 }}$

Answer 2

$\sf \red❏ \: \underline{ \orange{\: \: answer \: \: }} :$

Mole Fraction of Nitrogen => 0.428

Mole Fraction of Oxygen => 0.571

$\color{springgreen}{ \sf \: EXPLANATION }:$

For The Explanation,

Refer the Given Attachment