Question

A gauge pressure sensor measured 10 atm within a gas cylinder when the atmospheric temperature was 67 degree Celsius. Atmospheric pressure is 1 atm.The temperature of gas dropped to 37 degree Celcius. What is the new reading in the pressure sensor? 5.52 atm 6.07 atm 9.02 atm 10.02 atm

Answer 1

Answer:

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Answer 2

Answer:

The initial pressure in the pressure sensor, P₁ = 10 atm

Initial temperature, T₁ = 67℃ = 67+273.15 K = 340.15 K

Temperature of gas drops to T₂ = 37℃ = 37+273.15 K = 310.15 K

Let the final pressure or the new reading in the pressure sensor be “P₂” atm.

Using Gay-Lussac’s Law and substituting the given values, we get

P₁/T₁= P₂/T₂

⇒ 10 / 340.15 = P₂ / 310.15

⇒ T₂= [10 * 310.15] / 340.15  

⇒ T₂ = 9.11 atm

Thus, the new reading in the pressure sensor is 9.11 atm.