Question

A Gaussian surface encloses ah electric dipole of length 12cm .what is the total electric flux through the Gaussian surface?​

Answer 1

Explanation:

Gauss’s law is very helpful in determining expressions for the electric field, even though the law is not directly about the electric field; it is about the electric flux. It turns out that in situations that have certain symmetries (spherical, cylindrical, or planar) in the charge distribution, we can deduce the electric field based on knowledge of the electric flux. In these systems, we can find a Gaussian surface S over which the electric field has constant magnitude. Furthermore, if \stackrel{\to }{\text{E}} is parallel to \stackrel{^}{\text{n}} everywhere on the surface.

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Answer 2

Answer:

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Explanation:

When dipole moment vector is parallel to electric field vector.