A gave 60% of the amount he had to B. who spent 30% of the amount received on day 1 and 40% of the remaining amount on day 2. If B is left with Rs. 10080. what was the amount A had initially?
Answers
Answer:
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The initial amount is Rs. 40,000.
Given,
A gave 60% of the amount he had to B
B spent 30% of the amount received on day 1
B spent 40% of the remaining amount on day 2
B is left with Rs. 10080
To Find,
The amount A initially had =?
Solution,
Let the amount A has initially be x
A gave 60% of the amount he had to B. So,
Total amount B received = 60% of x
Total amount B received = 60x / 100
B then spent 30% of that on day 1 = 30% of (60x / 100)
B then spent 30% of that on day 1 = (30/100)*(60x / 100)
B then spent 30% of that on day 1 = 18x / 100
The amount left = 60x / 100 - 18x / 100
The amount left = 42x / 100
B spent 40% of the remaining amount on day 2 = 40% of (42x / 100)
Money spent on day 2 by B = (40/100)*(42x / 100)
Money spent on day 2 by B = 168x / 1000
Money left = 42x / 100 - 168x/1000
Money left = (420x - 168x)/1000 = 252x /1000
B is left with Rs. 10080 = 252x /1000
x = (10080*1000) / 252
x = 40 * 1000
x = Rs. 40000
Hence, the amount A had initially was Rs. 40,000.