Question

A gene locus has two alleles A, a. If the frequency
of dominant allele A is 0.4 then what will be the
frequency of homozygous dominant, heterozygous
and homozygous recessive individuals in the
population ?

(1) 0.36 (AA); 0.48(Aa); 0.16 (aa)

(2) 0.16 (AA); 0.24 (Aa); 0.36 (aa)

(3) 0.16 (AA); 0.48 (Aa); 0.36 (aa)

(4) 0.16 (AA); 0.36 (Aa); 0.48 (aa)

Give reason also. ​

Answer 1

Heya!!
___________________★_★

→ According to Hardy's Weinberg principle

p + q = 1

p = frequency of dominant allele

q = frequency of recessive allele

given,

p = 0.4

so, q = (1-0.4)= 0.6

★ now, frequency of HOMOZYGOUS DOMINANT =
AA = (0.4×04)=0.16

★ frequency of heterozygous = Aa = 0.4×0.6 = 0.24

★ frequency of homozygous recessive = aa = 0.6 × 0.6 = 0.36

your answer is option 2

hope it helps!!

#PhoeniX

Answer 2

RIGHT ANSWER IS 3

(3) 0.16 (AA); 0.48 (Aa); 0.36 (aa)

BRAINLIEST AND THANKS PLEASE