Question

A generator develops 200 V and has an internal resistance of 100Ω . Find the power delivered to a load of (i) 100 Ω (ii) 300 Ω . and find the efficienc?

Answer 1

Answer:

we need to find current in the generator

generator develops 200v and has an internal resistance of 100ohm

to find the power delivered to a load of 100ohm

r = \frac{p}{i}r=

i

p

power = 400wattpower=400watt

100ohm = \frac{200v}{i}100ohm=

i

200v

c = 2amperec=2ampere

the current flowing through the generator is 2ampere

The power delevered is

p = vip=vi

p = 200v \times 2amperep=200v×2ampere