Question

A geo-stationary is orbiting around the earth at height of 30000 km in circular orbit the geostationary satellite comes back to its position after one revolution in exactly 24 hrs let the acceleration due to gravity be 10 m/s^2 and mass of satellite be 1000kg calculate the work done in 12hours when moving under gravitational force

Answer 1

Answer:

SINCE FG IS PERPENDICULAR TO DISPLACEMENT AT EACH INSTANT DUE TO CIRCULAR MMOTION OF SATELLITE

W=F.DS=F.COS90=0