Question

A geologist working in the field drinks her morning coffee using an aluminium cup with
the mass of 120g at 20°C. if she pours in 300g of coffee at 70°C, calculate the final
temperature after the coffee and the cup attain thermal equilibrium?
(Specific heat capacity of aluminium is 910 J/kg°C and coffee is 4200 J/kg°C.
There is no heat exchange with the surroundings).

Answer 1

Explanation:

Qcoffee = mcoffee AT coffee

<br>

Qcoffee (0.300kg) (4190J/kg. K) (T - 70.0 <br> The positive heat is gained by the aluminium cup is ItBrgt Maluminium Caluminium Taluminiu

Qaluminium ItBrgt

= (0.120kg) (910J/kg. K) (T- 20.0° C) = <br> We equate the sum of these two quantities of heat to zero, obtaining an algebraic equation for T. <br>

Qcoffee Qaluminium 0

<br>

(0.300kg) (4190J/kg. K) (T - 70.0°C) + (0 <br>

T= 66.0°C...

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