Question

a geometric sequence with a fifth term of 1/3 and a constant ratio of 1/3

I dont understand it ​

Answer 1

Answer:

The first term of the geometrical sequence is 27

Step-by-step explanation:

let first term be

$a$

and the constant ratio is

$\frac{1}{3}$

then fifth term will be

$a \times {( \frac{1}{3}) }^{5 - 1} = a \times ( \frac{1}{3} )^{4} = a \times \frac{1}{ {3}^{4} } = \frac{a}{81}$

given the fifth term is

$\frac{1}{3}$

then

$\frac{a}{81} = \frac{1}{3}$

$a = \frac{81}{ 3} = 27$

Hence first term is 27