A geostationary satellite is moving in a circular orbit at a height of 3600 kilometre from the surface of earth.calculate its speed if it takes 24 hours to revolve around the earth?(radius of the earth =6400 km).answer In km/s?
Answers
a geostationary satellite is moving in a circular orbit at a height 36000 km from the surface of earth. calculate its speed if it takes 24 hours to revolve around the earth?(give radius of earth equal 6400 km)
The radius of the orbit = radius of the earth + height of the satellite above the
earth’s surface
The radius of the orbit = 6400 + 36000 = 42400 km
Circumference of the orbit = 2πR
= 2x3.14x42400
= 266272 km
Speed = Distance/Time
= 266272/24
= 11094.67 km/h
Explanation:
Answer:
Explanation:
The radius of the orbit = radius of the earth + height of the satellite above the
earth’s surface
The radius of the orbit = 6400 + 36000 = 42400 km
Circumference of the orbit = 2πR
= 2x3.14x42400
= 266272 km
Speed = Distance/Time
= 266272/24
= 11094.67 km/h