a geostationary satellite is moving in a circular orbit at a height 36000 km from the surface of earth. calculate its speed if it takes 24 hours to revolve around the earth?(give radius of earth equal 6400 km)
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The radius of the orbit = radius of the earth + height of the satellite above the
earth’s surface
The radius of the orbit = 6400 + 36000 = 42400 km
Circumference of the orbit = 2πR
= 2x3.14x42400
= 266272 km
Speed = Distance/Time
= 266272/24
= 11094.67 km/h
earth’s surface
The radius of the orbit = 6400 + 36000 = 42400 km
Circumference of the orbit = 2πR
= 2x3.14x42400
= 266272 km
Speed = Distance/Time
= 266272/24
= 11094.67 km/h
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