A geostationary satellite is orbiting the earth at a height of 5R above the surface of earth where R is the radius of earth find the time period of another satellite at the height of 2R from the surface of Earth
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Distance of satellite from center of earth are 7R and 3.5 R respectively
Time period of geostationary satellite is 24 hours
T2T1=(R2R1)32T2T1=(R2R1)32
T2=24(3.5R7R)3/2T2=24(3.5R7R)3/2
=62–√hours
Time period of geostationary satellite is 24 hours
T2T1=(R2R1)32T2T1=(R2R1)32
T2=24(3.5R7R)3/2T2=24(3.5R7R)3/2
=62–√hours
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