Question

A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth. R being the radius of the earth.The time period of another satellite in hours at a height 2R form the surface of the earth is?

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Answer 1

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$\implies$Please Drop Some Thanks.

Answer 2

Answer:

From Kepler's law T∝r

3/2

;

T

2

=T

1

(

r

1

r

2

)

3/2

=(24hrs)(

6R

3R

)

3/2

=

2

2

24hrs

=

2

2

24hrs

=6

2

hrs