A geostationary satellite is orbiting the earth at a height of 6 or above the surface of earth is the period of revolution of another satellite is 6 under root 2 are the height of satellite above the surface of earth will be
Answers
Answered by
0
Distance of satellite from center of earth are 7R and 3.5 R respectively
Time period of geostationary satellite is 24 hours
T2T1=(R2R1)32
T2=24(3.5R7R)3/2
=62–√hours
Similar questions