A geostationary satellite is orbiting the Earth at a height 5R above the surface of Earth, where R is the radius of Earth. Find the time period of another satellite at height of 2R.
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work done on the satellite would be the change in its potential energy as it raised form a height of 'Re' to '2Re'.
now, for a satellite at height 'h' the gravitational potential energy is given as
U = -GmM / (Re+h)
here
m is the mass of the satellite
M is the mass of the Earth
Re is the radius of the Earth
thus, for a satellite a height Re, the gravitational potential energy will be
U = -GmM / (Re+Re) = -GmM / 2Re
similarly, for a satellite a height 2Re, the gravitational potential energy will be
U' = -GmM / (Re+2Re) = -GmM / 3Re
thus, the chamge in potential energy would be
work done = dU = U' - U
or
W = -GmM / 3Re - [-GmM / 2Re] = (GmM/Re). [ 1/2 - 1/3 ]
thus, we get
W = GmM / 6R
ι нσρє уσυ нєℓρ !!!!
work done on the satellite would be the change in its potential energy as it raised form a height of 'Re' to '2Re'.
now, for a satellite at height 'h' the gravitational potential energy is given as
U = -GmM / (Re+h)
here
m is the mass of the satellite
M is the mass of the Earth
Re is the radius of the Earth
thus, for a satellite a height Re, the gravitational potential energy will be
U = -GmM / (Re+Re) = -GmM / 2Re
similarly, for a satellite a height 2Re, the gravitational potential energy will be
U' = -GmM / (Re+2Re) = -GmM / 3Re
thus, the chamge in potential energy would be
work done = dU = U' - U
or
W = -GmM / 3Re - [-GmM / 2Re] = (GmM/Re). [ 1/2 - 1/3 ]
thus, we get
W = GmM / 6R
smartAbhishek11:
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