Physics, asked by meenadevi, 1 year ago

A GEYSER OF 2.5 KW IS USED OR 8 HOURS .CALCULATE MONTHLY CONSUMPTION.ALSO COST OF ELECTRICITY CONSUMED IN RATE OF 3.50

Answers

Answered by debambarish2013
2
Daily Consumption of Energy=Power×Time
= 2.5×8=20 units
Taking 30 days in a month,
Monthly Consumption of Energy =20×30
=600 units
Cost=$3.5 per unit
=600×3.5
=$2100

meenadevi: THANK U
Answered by Anonymous
4
Power = 2.5 kW
Time = 8 hrs.
Power = Energy / Time
Energy consumed = Power × Time
= 2.5× 8
= 20 kWh

Energy consumed in a month =20kWh × 30 = 600kWh

Cost of energy for 1 kWh = Rs 3.50
Total cost of energy for 600 kWh = 600 × 3.50 = Rs 2100



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meenadevi: BUT IT IS ALREAY IN KW
Anonymous: sorry i didnt see
Anonymous: changed
debambarish2013: Excuse me, but i think there is a mistake in ur answer
meenadevi: THANKU
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