Math, asked by sg482077, 2 months ago

a girl.
7. A die is thrown once. Find the probability of getting
(1) an even number.
(ii) an odd number.
(iii) a number greater than 3.
black ball​

Answers

Answered by sus41
1

Answer:

hello

Step-by-step explanation:

n(s) = 1,2,3,4,5,6 (6)

event of getting a even number is 3

therefore probability is 3/6=1/2

event of getting an odd number is 3

probability is 3/6=1/2

event of getting a number greater than 3 is 3(4,5,6)

probability is 3/6=1/2

hope it was helpful!!

Answered by shibli99
0
Even numbers in a dice (1,4,6)
Why not 2 because 2 is a even prime number
No of favourable outcomes / Total no of outcomes
3/6
1/2 is the probability of getting an even number
An odd no =(3,5)
2 are the no of favourable outcomes for an odd number =
Probability (odd no)=2/6
1/3
A no greater than three
No of favourable outcomes / Total no of outcomes
(4,5,6) greater no than three
3/6
1/3 is the probability for getting a no greater than 3
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